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本文专栏：【实战小项目】
🐳希望大家多多支持🥰一起进步呀！

✨前言

哈喽大家好，我是iecne，本期为大家带来的是CPP/C++【C++实战小项目】实现基本通讯录模拟详解分析。包教包会，快来看看吧！

任务描述

如何根据据C++基础入门编写一款不可视化通讯录，我们这次就来讲讲并且写一写添加用户

一.分析通讯录

首先制作一款通讯录我们可以将它分为以下部分

增加联系人
删除联系人
查找联系人
修改联系人
打印通讯录
排序通讯录

这一期我们就来实现准备删除查找与修改

二.删除

删除是string2_函数，我们就来看看

2.1 Flowchat流程图

2.2 string2_

void string2_()
{
string name1 = "请输入名字：>\n";
out06(name1);
string chaname;
input_string(chaname);
chaname = stringaaaa;
int s = 0;
int ss = 0;
cout << " 姓名";
for (int j = 1; j <= 12; j++)
{
cout << " ";
}
cout << "性别";
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << "年龄";
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << "电话";
for (int j = 1; j <= 20; j++)
{
cout << " ";
}
cout << "地址";
cout << "\n";
for (int i = 1; i <= z - 1; i++)
{
if (namez[i] == chaname)
{
s++;
ss = i;
cout << " ";
cout << namez[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << bgz[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << agez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << phonez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << homez[i];
cout << "\n";
}
}
if (s == 0)
{
cout << "没有找到这个人";
}
cout << "确认删除该联系人吗";
cout << endl;
cout << "1.yes";
cout << endl << "2.no" << endl;
int yesno1;
cin >> yesno1;
if (yesno1 == 1)
{
over(ss);
}
else
{
system("pause");
playfirst();
}
}
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基本如图所示

三.查找

删除是string3_函数，我们来看看

3.1 Flowchart流程图

3.2 三千字代码实现

然后我们再看看code

void string3_()
{
string string0 = "=====================================\n";
string string1 = "============1.通过名字查=============\n";
string string2 = "============2.通过性别查=============\n";
string string3 = "============3.通过年龄查=============\n";
string string4 = "============4.通过地址查=============\n";
out06(string0);
out06(string1);
out06(string2);
out06(string3);
out06(string4);
out06(string0);
int string7 = 0;
string7 = input(string7);
switch (string7)
{
case 1:
cha1_();
case 2:
cha2_();
case 3:
cha3_();
case 4:
cha4_();
}
}
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通过switch来分别到cha1_ ~ cha4_

void cha1_()
{
string name1 = "请输入名字：>\n";
out06(name1);
string chaname;
input_string(chaname);
chaname = stringaaaa;
int s = 0;
cout << " 姓名";
for (int j = 1; j <= 12; j++)
{
cout << " ";
}
cout << "性别";
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << "年龄";
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << "电话";
for (int j = 1; j <= 20; j++)
{
cout << " ";
}
cout << "地址";
cout << "\n";
for (int i = 1; i <= z - 1; i++)
{
if (namez[i] == chaname)
{
s++;

cout << " ";
cout << namez[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << bgz[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << agez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << phonez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << homez[i];
cout << "\n";
}
}
if (s == 0)
{
cout << "没有找到这个人";
}
system("pause");
playfirst();
}

void cha2_()
{
string name1 = "请输入性别：>\n";
out06(name1);
string chaname;
input_string(chaname);
chaname = stringaaaa;
if (chaname == "男")chaname = "男";
else if (chaname == "女") chaname = "女";
else chaname = "不男不女";
cout << " 姓名";
for (int j = 1; j <= 12; j++)
{
cout << " ";
}
cout << "性别";
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << "年龄";
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << "电话";
for (int j = 1; j <= 20; j++)
{
cout << " ";
}
cout << "地址";
cout << "\n";
int s = 0;
for (int i = 1; i <= z - 1; i++)
{
if (bgz[i] == chaname)
{
s++;
cout << " ";
cout << namez[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << bgz[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << agez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << phonez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << homez[i];
cout << "\n";
}
}
if (s == 0)
{
cout << "没有找到这个人";
}
system("pause");
playfirst();
}

void cha3_()
{
string name1 = "请输入年龄：>\n";
out06(name1);
int chaage;
int s = 0;
cin >> chaage;
cout << " 姓名";
for (int j = 1; j <= 12; j++)
{
cout << " ";
}
cout << "性别";
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << "年龄";
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << "电话";
for (int j = 1; j <= 20; j++)
{
cout << " ";
}
cout << "地址";
cout << "\n";
cout << " ";
for (int i = 1; i <= z - 1; i++)
{
if (agez[i] == chaage)
{
s++;
cout << " 姓名";
for (int j = 1; j <= 12; j++)
{
cout << " ";
}
cout << "性别";
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << "年龄";
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << "电话";
for (int j = 1; j <= 20; j++)
{
cout << " ";
}
cout << "地址";
cout << "\n";
cout << " ";
cout << namez[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << bgz[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << agez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << phonez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << homez[i];
cout << "\n";
}
}
if (s == 0)
{
cout << "没有找到这个人";
}
system("pause");
playfirst();
}

void cha4_()
{
string name1 = "请输入地址：>\n";
out06(name1);
string chaname;
input_string(chaname);
chaname = stringaaaa;
int s = 0;
cout << " 姓名";
for (int j = 1; j <= 12; j++)
{
cout << " ";
}
cout << "性别";
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << "年龄";
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << "电话";
for (int j = 1; j <= 20; j++)
{
cout << " ";
}
cout << "地址";
cout << "\n";
cout << " ";
for (int i = 1; i <= z - 1; i++)
{
if (homez[i] == chaname)
{
s++;

cout << namez[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << bgz[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << agez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << phonez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << homez[i];
cout << "\n";
}
}
if (s == 0)
{
cout << "没有找到这个人";
}
system("pause");
playfirst();
}
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四.修改

4.1 Flowchart流程图

4.2 代码实现

void string4_()
{
printf("请输入需要修改信息用户的名字:>\n");
string chaname;
input_string(chaname);
chaname = stringaaaa;
int s = 0;
cout << " 姓名";
for (int j = 1; j <= 12; j++)
{
cout << " ";
}
cout << "性别";
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << "年龄";
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << "电话";
for (int j = 1; j <= 20; j++)
{
cout << " ";
}
cout << "地址";
cout << "\n";
cout << " ";
int ss = 0;
for (int i = 1; i <= z - 1; i++)
{
if (namez[i] == chaname)
{
s++;
ss = i;
cout << namez[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << bgz[i];
for (int j = 1; j <= 10; j++)
{
cout << " ";
}
cout << agez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << phonez[i];
for (int j = 1; j <= 20 - 1; j++)
{
cout << " ";
}
cout << homez[i];
cout << "\n";
}
}
if (s == 0)
{
cout << "没有找到这个人";
system("pause");
playfirst();
}
printf(" \n0.退出 1.姓名 2.性别 3.年龄 4.电话 5.地址:>\n");
int num;
cin >> num;
switch (num)
{
case 1:
printf("请输入你想修改的姓名:>\n");
cin >> namez[ss];
break;
case 2:
printf("请输入你想修改的性别:>\n");
cin >> bgz[ss];
break;
case 3:
printf("请输入你想修改的年龄:>\n");
cin >> agez[ss];
break;
case 4:
printf("请输入你想修改的电话:>\n");
cin >> phonez[ss];
break;
case 5:
printf("请输入你想修改的地址:>\n");
cin >> homez[ss];
break;
case 0:
printf("不修改退回界面\n");
break;
default:printf("无效操作数！\n");
}
system("pause");
playfirst();
}
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总结

今天我们实现了通讯录的教程，至此该课示例的思想博主已经真真切切彻彻底底分享完了，相信大家对这个逻辑有了一定的理解，大家可以自己动手敲敲代码，感受一下，包教包会。若有任何侵权和不妥之处，请私信于我，定积极配合处理，看到必回！！！

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若有任何侵权和不妥之处，请私信于我，定积极配合处理，看到必回！！！